JavaBeanInfo if(paramNames ! = null types.length = paramnames.
What causes subsequent deserialization to fail?įrom the above exception information, you can find the code segment that threw the exception, as follows: Class: com.Why is deserialization normal at first?.It seems natural to throw the above exception, but there are two problems: A date without a time-zone in the ISO-8601. The definition of the Test class is as follows: data class Test( val name: String)Īs you can see, the Test class does not have a default constructor. public final class LocalDate extends Object implements Temporal, TemporalAdjuster, ChronoLocalDate, Serializable. See above exception message is the Test class The default constructor could not be foundAfter a while, the same problem will occur again. In rialization each class can have its own serialization strategy (or even several ones). Serializable data class Event( SerialName(temperature) val. This is because java serialization is rather primitive - there is only one way to serialize (and hence to deserialize) an object. However, after running for some time, when the interface is called again, the following exceptions will be found: Method threw '' exception: default constructor not found. Solved-How to prevent serializing null values using kotlin serialization-kotlin.
When the service is started, the interface is called normally. Serialization is the process of converting data used by an application to a format that can be transferred over a network or stored in a database or a file.
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